Base | Representation |
---|---|
bin | 10101011101101100111… |
… | …000110101010010101111 |
3 | 12020000020022220001200021 |
4 | 111131230320311102233 |
5 | 143131300124321312 |
6 | 3045334514143011 |
7 | 211364614256242 |
oct | 25355470652257 |
9 | 5200208801607 |
10 | 1475000620207 |
11 | 5195a9440334 |
12 | 1b9a46881a67 |
13 | a912706949a |
14 | 51567405259 |
15 | 2857c79ac07 |
hex | 1576ce354af |
1475000620207 has 2 divisors, whose sum is σ = 1475000620208. Its totient is φ = 1475000620206.
The previous prime is 1475000620141. The next prime is 1475000620231. The reversal of 1475000620207 is 7020260005741.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1475000620207 is a prime.
It is a super-2 number, since 2×14750006202072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1475000620297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 737500310103 + 737500310104.
It is an arithmetic number, because the mean of its divisors is an integer number (737500310104).
Almost surely, 21475000620207 is an apocalyptic number.
1475000620207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1475000620207 is an equidigital number, since it uses as much as digits as its factorization.
1475000620207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23520, while the sum is 34.
Adding to 1475000620207 its reverse (7020260005741), we get a palindrome (8495260625948).
The spelling of 1475000620207 in words is "one trillion, four hundred seventy-five billion, six hundred twenty thousand, two hundred seven".
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