14761125437 has 2 divisors, whose sum is σ = 14761125438. Its totient is φ = 14761125436.

The previous prime is 14761125377. The next prime is 14761125451. The reversal of 14761125437 is 73452116741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14664967801 + 96157636 = 121099^2 + 9806^2 .

It is a cyclic number.

It is not a de Polignac number, because 14761125437 - 2⁶ = 14761125373 is a prime.

It is a super-3 number, since 3×14761125437³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14761125394 and 14761125403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14761122437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7380562718 + 7380562719.

It is an arithmetic number, because the mean of its divisors is an integer number (7380562719).

Almost surely, 2^14761125437 is an apocalyptic number.

It is an amenable number.

14761125437 is a deficient number, since it is larger than the sum of its proper divisors (1).

14761125437 is an equidigital number, since it uses as much as digits as its factorization.

14761125437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 141120, while the sum is 41.

The spelling of 14761125437 in words is "fourteen billion, seven hundred sixty-one million, one hundred twenty-five thousand, four hundred thirty-seven".