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147672302272133 is a prime number
BaseRepresentation
bin100001100100111010100011…
…000111101011111010000101
3201100212100000122112112222112
4201210322203013223322011
5123323430333340202013
61242023415155310405
743050654212420522
oct4144724307537205
9640770018475875
10147672302272133
11430645209072a1
121468ba6b2ab405
1364525910a0272
142867540080149
151211467338ba8
hex864ea31ebe85

147672302272133 has 2 divisors, whose sum is σ = 147672302272134. Its totient is φ = 147672302272132.

The previous prime is 147672302272111. The next prime is 147672302272213. The reversal of 147672302272133 is 331272203276741.

147672302272133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103416838731649 + 44255463540484 = 10169407^2 + 6652478^2 .

It is a cyclic number.

It is not a de Polignac number, because 147672302272133 - 224 = 147672285494917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (147672302275133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73836151136066 + 73836151136067.

It is an arithmetic number, because the mean of its divisors is an integer number (73836151136067).

Almost surely, 2147672302272133 is an apocalyptic number.

It is an amenable number.

147672302272133 is a deficient number, since it is larger than the sum of its proper divisors (1).

147672302272133 is an equidigital number, since it uses as much as digits as its factorization.

147672302272133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3556224, while the sum is 50.

The spelling of 147672302272133 in words is "one hundred forty-seven trillion, six hundred seventy-two billion, three hundred two million, two hundred seventy-two thousand, one hundred thirty-three".