Base | Representation |
---|---|
bin | 11011100001111001… |
… | …11100001010010101 |
3 | 1102011001000222201212 |
4 | 31300330330022111 |
5 | 220232130101031 |
6 | 10442333031205 |
7 | 1032155201522 |
oct | 156074741225 |
9 | 42131028655 |
10 | 14779925141 |
11 | 62a4978573 |
12 | 2a45925505 |
13 | 1517083547 |
14 | a02cd8149 |
15 | 5b784212b |
hex | 370f3c295 |
14779925141 has 2 divisors, whose sum is σ = 14779925142. Its totient is φ = 14779925140.
The previous prime is 14779925119. The next prime is 14779925161. The reversal of 14779925141 is 14152997741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14237501041 + 542424100 = 119321^2 + 23290^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14779925141 is a prime.
It is a super-3 number, since 3×147799251413 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14779925141.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14779925161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7389962570 + 7389962571.
It is an arithmetic number, because the mean of its divisors is an integer number (7389962571).
Almost surely, 214779925141 is an apocalyptic number.
It is an amenable number.
14779925141 is a deficient number, since it is larger than the sum of its proper divisors (1).
14779925141 is an equidigital number, since it uses as much as digits as its factorization.
14779925141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 635040, while the sum is 50.
The spelling of 14779925141 in words is "fourteen billion, seven hundred seventy-nine million, nine hundred twenty-five thousand, one hundred forty-one".
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