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148044577117 is a prime number
BaseRepresentation
bin1000100111100000100…
…1001111100101011101
3112011010110222201221211
42021320021033211131
54411143402431432
6152002153024421
713460453066623
oct2117011174535
9464113881854
10148044577117
1157870338a88
12248379b5111
1310c644120b8
147245bbb513
153cb70c4d47
hex227824f95d

148044577117 has 2 divisors, whose sum is σ = 148044577118. Its totient is φ = 148044577116.

The previous prime is 148044577099. The next prime is 148044577133. The reversal of 148044577117 is 711775440841.

148044577117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110390727001 + 37653850116 = 332251^2 + 194046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-148044577117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (148044577217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74022288558 + 74022288559.

It is an arithmetic number, because the mean of its divisors is an integer number (74022288559).

Almost surely, 2148044577117 is an apocalyptic number.

It is an amenable number.

148044577117 is a deficient number, since it is larger than the sum of its proper divisors (1).

148044577117 is an equidigital number, since it uses as much as digits as its factorization.

148044577117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 878080, while the sum is 49.

The spelling of 148044577117 in words is "one hundred forty-eight billion, forty-four million, five hundred seventy-seven thousand, one hundred seventeen".