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1481460325117 is a prime number
BaseRepresentation
bin10101100011101101111…
…010101001101011111101
312020121220111222001221021
4111203231322221223331
5143233012320400432
63052323512104141
7212013652664203
oct25435572515375
95217814861837
101481460325117
11521313806233
121bb14a095051
13a991644c396
14519bb2bb073
152880993c697
hex158edea9afd

1481460325117 has 2 divisors, whose sum is σ = 1481460325118. Its totient is φ = 1481460325116.

The previous prime is 1481460325087. The next prime is 1481460325199. The reversal of 1481460325117 is 7115230641841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1282705744356 + 198754580761 = 1132566^2 + 445819^2 .

It is a cyclic number.

It is not a de Polignac number, because 1481460325117 - 223 = 1481451936509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1481460325817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740730162558 + 740730162559.

It is an arithmetic number, because the mean of its divisors is an integer number (740730162559).

Almost surely, 21481460325117 is an apocalyptic number.

It is an amenable number.

1481460325117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1481460325117 is an equidigital number, since it uses as much as digits as its factorization.

1481460325117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 161280, while the sum is 43.

Adding to 1481460325117 its reverse (7115230641841), we get a palindrome (8596690966958).

The spelling of 1481460325117 in words is "one trillion, four hundred eighty-one billion, four hundred sixty million, three hundred twenty-five thousand, one hundred seventeen".