Base | Representation |
---|---|
bin | 10101100011101101111… |
… | …110001101101110001011 |
3 | 12020121220120201112011222 |
4 | 111203231332031232023 |
5 | 143233013040243042 |
6 | 3052323544112255 |
7 | 212013663634262 |
oct | 25435576155613 |
9 | 5217816645158 |
10 | 1481461259147 |
11 | 521314293a61 |
12 | 1bb14a46568b |
13 | a99166b856c |
14 | 519bb4815d9 |
15 | 28809a742d2 |
hex | 158edf8db8b |
1481461259147 has 2 divisors, whose sum is σ = 1481461259148. Its totient is φ = 1481461259146.
The previous prime is 1481461259141. The next prime is 1481461259149. The reversal of 1481461259147 is 7419521641841.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1481461259147 - 226 = 1481394150283 is a prime.
Together with 1481461259149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1481461259141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740730629573 + 740730629574.
It is an arithmetic number, because the mean of its divisors is an integer number (740730629574).
Almost surely, 21481461259147 is an apocalyptic number.
1481461259147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1481461259147 is an equidigital number, since it uses as much as digits as its factorization.
1481461259147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1935360, while the sum is 53.
The spelling of 1481461259147 in words is "one trillion, four hundred eighty-one billion, four hundred sixty-one million, two hundred fifty-nine thousand, one hundred forty-seven".
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