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1490359073941 is a prime number
BaseRepresentation
bin10101101100000000010…
…100101011110010010101
312021110212200112100110001
4111230000110223302111
5143404223410331231
63100354515131301
7212450326052263
oct25540024536225
95243780470401
101490359073941
1152506a930a01
12200a122a3b31
13aa703c3b52a
14521c3097433
1528b7acb8b61
hex15b0052bc95

1490359073941 has 2 divisors, whose sum is σ = 1490359073942. Its totient is φ = 1490359073940.

The previous prime is 1490359073897. The next prime is 1490359073953. The reversal of 1490359073941 is 1493709530941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1374404522500 + 115954551441 = 1172350^2 + 340521^2 .

It is a cyclic number.

It is not a de Polignac number, because 1490359073941 - 217 = 1490358942869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1490359073741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 745179536970 + 745179536971.

It is an arithmetic number, because the mean of its divisors is an integer number (745179536971).

Almost surely, 21490359073941 is an apocalyptic number.

It is an amenable number.

1490359073941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1490359073941 is an equidigital number, since it uses as much as digits as its factorization.

1490359073941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3674160, while the sum is 55.

The spelling of 1490359073941 in words is "one trillion, four hundred ninety billion, three hundred fifty-nine million, seventy-three thousand, nine hundred forty-one".