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1490560371115 = 5298112074223
BaseRepresentation
bin10101101100001100010…
…100100100100110101011
312021111101201022022020221
4111230030110210212223
5143410131423333430
63100430505430511
7212455322051434
oct25541424444653
95244351268227
101490560371115
1152516351a502
12200a6979b437
13aa73685b09a
1452201ad648b
1528b8d7cc57a
hex15b0c5249ab

1490560371115 has 4 divisors (see below), whose sum is σ = 1788672445344. Its totient is φ = 1192448296888.

The previous prime is 1490560371107. The next prime is 1490560371119. The reversal of 1490560371115 is 5111730650941.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1490560371115 - 23 = 1490560371107 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1490560371119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149056037107 + ... + 149056037116.

It is an arithmetic number, because the mean of its divisors is an integer number (447168111336).

Almost surely, 21490560371115 is an apocalyptic number.

1490560371115 is a deficient number, since it is larger than the sum of its proper divisors (298112074229).

1490560371115 is an equidigital number, since it uses as much as digits as its factorization.

1490560371115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 298112074228.

The product of its (nonzero) digits is 113400, while the sum is 43.

The spelling of 1490560371115 in words is "one trillion, four hundred ninety billion, five hundred sixty million, three hundred seventy-one thousand, one hundred fifteen".

Divisors: 1 5 298112074223 1490560371115