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149121221001001 = 244196106770179
BaseRepresentation
bin100001111001111111111101…
…011001111111111100101001
3201112222211221021202020221021
4201321333331121333330221
5124021200230034013001
61245053202044212441
743260436604413414
oct4171777531777451
9645884837666837
10149121221001001
1143572a55744627
121488483723a121
1365290bc722b42
1428b7711554b7b
151238eb9e56ba1
hex879ffd67ff29

149121221001001 has 4 divisors (see below), whose sum is σ = 149127327795600. Its totient is φ = 149115114206404.

The previous prime is 149121221000993. The next prime is 149121221001043. The reversal of 149121221001001 is 100100122121941.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 149121221001001 - 23 = 149121221000993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (149121221001091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3053360671 + ... + 3053409508.

It is an arithmetic number, because the mean of its divisors is an integer number (37281831948900).

Almost surely, 2149121221001001 is an apocalyptic number.

It is an amenable number.

149121221001001 is a deficient number, since it is larger than the sum of its proper divisors (6106794599).

149121221001001 is an equidigital number, since it uses as much as digits as its factorization.

149121221001001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6106794598.

The product of its (nonzero) digits is 288, while the sum is 25.

Adding to 149121221001001 its reverse (100100122121941), we get a palindrome (249221343122942).

The spelling of 149121221001001 in words is "one hundred forty-nine trillion, one hundred twenty-one billion, two hundred twenty-one million, one thousand, one".

Divisors: 1 24419 6106770179 149121221001001