Base | Representation |
---|---|
bin | 10101101100110110001… |
… | …101111111010001010001 |
3 | 12021120012200222012111111 |
4 | 111230312031333101101 |
5 | 143413101400212101 |
6 | 3101024335413321 |
7 | 212511615543115 |
oct | 25546615772121 |
9 | 5246180865444 |
10 | 1491263288401 |
11 | 525494281687 |
12 | 201025084241 |
13 | aa81937c283 |
14 | 5226b1cd745 |
15 | 28bd0379251 |
hex | 15b3637f451 |
1491263288401 has 2 divisors, whose sum is σ = 1491263288402. Its totient is φ = 1491263288400.
The previous prime is 1491263288369. The next prime is 1491263288477. The reversal of 1491263288401 is 1048823621941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1271301350400 + 219961938001 = 1127520^2 + 469001^2 .
It is a cyclic number.
It is not a de Polignac number, because 1491263288401 - 25 = 1491263288369 is a prime.
It is a super-2 number, since 2×14912632884012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1491263283401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 745631644200 + 745631644201.
It is an arithmetic number, because the mean of its divisors is an integer number (745631644201).
Almost surely, 21491263288401 is an apocalyptic number.
It is an amenable number.
1491263288401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1491263288401 is an equidigital number, since it uses as much as digits as its factorization.
1491263288401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 663552, while the sum is 49.
The spelling of 1491263288401 in words is "one trillion, four hundred ninety-one billion, two hundred sixty-three million, two hundred eighty-eight thousand, four hundred one".
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