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14913050101 is a prime number
BaseRepresentation
bin11011110001110001…
…10001010111110101
31102111022112102211221
431320320301113311
5221020220100401
610503450230341
71035362556115
oct157070612765
942438472757
1014913050101
1163630342a4
122a824253b1
131538824501
14a1686d045
155c438b7a1
hex378e315f5

14913050101 has 2 divisors, whose sum is σ = 14913050102. Its totient is φ = 14913050100.

The previous prime is 14913050083. The next prime is 14913050111. The reversal of 14913050101 is 10105031941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12321222001 + 2591828100 = 111001^2 + 50910^2 .

It is a cyclic number.

It is not a de Polignac number, because 14913050101 - 213 = 14913041909 is a prime.

It is a super-2 number, since 2×149130501012 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14913050111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7456525050 + 7456525051.

It is an arithmetic number, because the mean of its divisors is an integer number (7456525051).

Almost surely, 214913050101 is an apocalyptic number.

It is an amenable number.

14913050101 is a deficient number, since it is larger than the sum of its proper divisors (1).

14913050101 is an equidigital number, since it uses as much as digits as its factorization.

14913050101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 25.

The spelling of 14913050101 in words is "fourteen billion, nine hundred thirteen million, fifty thousand, one hundred one".