1491326424011 has 2 divisors, whose sum is σ = 1491326424012. Its totient is φ = 1491326424010.

The previous prime is 1491326423963. The next prime is 1491326424013. The reversal of 1491326424011 is 1104246231941.

It is a strong prime.

It is an emirp because it is prime and its reverse (1104246231941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1491326424011 - 2¹⁰ = 1491326422987 is a prime.

It is a super-3 number, since 3×1491326424011³ (a number of 37 digits) contains 333 as substring.

Together with 1491326424013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1491326424013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 745663212005 + 745663212006.

It is an arithmetic number, because the mean of its divisors is an integer number (745663212006).

Almost surely, 2^{1491326424011} is an apocalyptic number.

1491326424011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1491326424011 is an equidigital number, since it uses as much as digits as its factorization.

1491326424011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 1491326424011 in words is "one trillion, four hundred ninety-one billion, three hundred twenty-six million, four hundred twenty-four thousand, eleven".