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1492094935477 is a prime number
BaseRepresentation
bin10101101101100111110…
…010011110000110110101
312021122100122212020211001
4111231213302132012311
5143421302300413402
63101243044443301
7212541334455136
oct25554762360665
95248318766731
101492094935477
11525880768413
122012176a9531
13aa91c762a33
1452309835c8d
1528c2d3a3187
hex15b67c9e1b5

1492094935477 has 2 divisors, whose sum is σ = 1492094935478. Its totient is φ = 1492094935476.

The previous prime is 1492094935469. The next prime is 1492094935519. The reversal of 1492094935477 is 7745394902941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1076958270756 + 415136664721 = 1037766^2 + 644311^2 .

It is an emirp because it is prime and its reverse (7745394902941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1492094935477 - 23 = 1492094935469 is a prime.

It is a super-2 number, since 2×14920949354772 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1492094935447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746047467738 + 746047467739.

It is an arithmetic number, because the mean of its divisors is an integer number (746047467739).

Almost surely, 21492094935477 is an apocalyptic number.

It is an amenable number.

1492094935477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1492094935477 is an equidigital number, since it uses as much as digits as its factorization.

1492094935477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68584320, while the sum is 64.

The spelling of 1492094935477 in words is "one trillion, four hundred ninety-two billion, ninety-four million, nine hundred thirty-five thousand, four hundred seventy-seven".