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14925239433493 = 47317558285819
BaseRepresentation
bin1101100100110000110110…
…0110000011100100010101
31221211211122121011002210221
43121030031212003210111
53424013342243332433
651424321011114341
73100212226645234
oct331141546034425
957754577132727
1014925239433493
114834838618424
1218107405a29b1
138435a072958c
14398557926b1b
151ad38e14572d
hexd930d983915

14925239433493 has 4 divisors (see below), whose sum is σ = 15242797719360. Its totient is φ = 14607681147628.

The previous prime is 14925239433491. The next prime is 14925239433497. The reversal of 14925239433493 is 39433493252941.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14925239433493 - 21 = 14925239433491 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14925239433491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158779142863 + ... + 158779142956.

It is an arithmetic number, because the mean of its divisors is an integer number (3810699429840).

Almost surely, 214925239433493 is an apocalyptic number.

It is an amenable number.

14925239433493 is a deficient number, since it is larger than the sum of its proper divisors (317558285867).

14925239433493 is an equidigital number, since it uses as much as digits as its factorization.

14925239433493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 317558285866.

The product of its digits is 75582720, while the sum is 61.

The spelling of 14925239433493 in words is "fourteen trillion, nine hundred twenty-five billion, two hundred thirty-nine million, four hundred thirty-three thousand, four hundred ninety-three".

Divisors: 1 47 317558285819 14925239433493