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14925391331 is a prime number
BaseRepresentation
bin11011110011001111…
…10110010111100011
31102112011202102211112
431321213312113203
5221031400010311
610505010533535
71035602506304
oct157147662743
942464672745
1014925391331
116369aa3464
122a865972ab
13153b255906
14a183627ab
155c54c828b
hex3799f65e3

14925391331 has 2 divisors, whose sum is σ = 14925391332. Its totient is φ = 14925391330.

The previous prime is 14925391297. The next prime is 14925391333. The reversal of 14925391331 is 13319352941.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14925391331 - 26 = 14925391267 is a prime.

It is a super-2 number, since 2×149253913312 (a number of 21 digits) contains 22 as substring.

Together with 14925391333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14925391333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7462695665 + 7462695666.

It is an arithmetic number, because the mean of its divisors is an integer number (7462695666).

Almost surely, 214925391331 is an apocalyptic number.

14925391331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14925391331 is an equidigital number, since it uses as much as digits as its factorization.

14925391331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 87480, while the sum is 41.

The spelling of 14925391331 in words is "fourteen billion, nine hundred twenty-five million, three hundred ninety-one thousand, three hundred thirty-one".