Search a number
-
+
14925773953 is a prime number
BaseRepresentation
bin11011110011010010…
…10011110010000001
31102112012110212200201
431321221103302001
5221031444231303
610505023045201
71035605661646
oct157151236201
942465425621
1014925773953
11636a234982
122a86740801
13153b35ab0c
14a18421dcd
155c555181d
hex379a53c81

14925773953 has 2 divisors, whose sum is σ = 14925773954. Its totient is φ = 14925773952.

The previous prime is 14925773927. The next prime is 14925773957. The reversal of 14925773953 is 35937752941.

14925773953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13027254769 + 1898519184 = 114137^2 + 43572^2 .

It is a cyclic number.

It is not a de Polignac number, because 14925773953 - 229 = 14388903041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14925773894 and 14925773903.

It is not a weakly prime, because it can be changed into another prime (14925773957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7462886976 + 7462886977.

It is an arithmetic number, because the mean of its divisors is an integer number (7462886977).

Almost surely, 214925773953 is an apocalyptic number.

It is an amenable number.

14925773953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14925773953 is an equidigital number, since it uses as much as digits as its factorization.

14925773953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7144200, while the sum is 55.

The spelling of 14925773953 in words is "fourteen billion, nine hundred twenty-five million, seven hundred seventy-three thousand, nine hundred fifty-three".