Base | Representation |
---|---|
bin | 10101101110011110010… |
… | …010011110011010010111 |
3 | 12021201201101101112021112 |
4 | 111232132102132122113 |
5 | 143430140334414444 |
6 | 3101513510405235 |
7 | 212603106421265 |
oct | 25563622363227 |
9 | 5251641345245 |
10 | 1493009294999 |
11 | 5261aa908242 |
12 | 20143196081b |
13 | aaa37016381 |
14 | 5239504d435 |
15 | 28c837b969e |
hex | 15b9e49e697 |
1493009294999 has 2 divisors, whose sum is σ = 1493009295000. Its totient is φ = 1493009294998.
The previous prime is 1493009294957. The next prime is 1493009295013. The reversal of 1493009294999 is 9994929003941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1493009294999 - 220 = 1493008246423 is a prime.
It is a super-2 number, since 2×14930092949992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1493009294599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746504647499 + 746504647500.
It is an arithmetic number, because the mean of its divisors is an integer number (746504647500).
Almost surely, 21493009294999 is an apocalyptic number.
1493009294999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1493009294999 is an equidigital number, since it uses as much as digits as its factorization.
1493009294999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51018336, while the sum is 68.
The spelling of 1493009294999 in words is "one trillion, four hundred ninety-three billion, nine million, two hundred ninety-four thousand, nine hundred ninety-nine".
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