1493123113049 has 4 divisors (see below), whose sum is σ = 1498399166736. Its totient is φ = 1487847059364.

The previous prime is 1493123112989. The next prime is 1493123113081. The reversal of 1493123113049 is 9403113213941.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1493123113049 is a prime.

It is a super-2 number, since 2×1493123113049² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1493123112997 and 1493123113015.

It is not an unprimeable number, because it can be changed into a prime (1493123113949) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2638026419 + ... + 2638026984.

It is an arithmetic number, because the mean of its divisors is an integer number (374599791684).

Almost surely, 2^{1493123113049} is an apocalyptic number.

It is an amenable number.

1493123113049 is a deficient number, since it is larger than the sum of its proper divisors (5276053687).

1493123113049 is an equidigital number, since it uses as much as digits as its factorization.

1493123113049 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5276053686.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 1493123113049 in words is "one trillion, four hundred ninety-three billion, one hundred twenty-three million, one hundred thirteen thousand, forty-nine".