Base | Representation |
---|---|
bin | 10101101110110111011… |
… | …001100110101100100111 |
3 | 12021202210202010202022221 |
4 | 111232313121212230213 |
5 | 143432021213004333 |
6 | 3102023400333211 |
7 | 212616413413252 |
oct | 25566731465447 |
9 | 5252722122287 |
10 | 1493430594343 |
11 | 5263a6700716 |
12 | 20152aa74207 |
13 | aaaa33a461c |
14 | 523d4d9a099 |
15 | 28caa788d2d |
hex | 15bb7666b27 |
1493430594343 has 4 divisors (see below), whose sum is σ = 1497371044840. Its totient is φ = 1489490143848.
The previous prime is 1493430594323. The next prime is 1493430594349. The reversal of 1493430594343 is 3434950343941.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1493430594343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1493430594349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1970224680 + ... + 1970225437.
It is an arithmetic number, because the mean of its divisors is an integer number (374342761210).
Almost surely, 21493430594343 is an apocalyptic number.
1493430594343 is a deficient number, since it is larger than the sum of its proper divisors (3940450497).
1493430594343 is an equidigital number, since it uses as much as digits as its factorization.
1493430594343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3940450496.
The product of its (nonzero) digits is 8398080, while the sum is 52.
The spelling of 1493430594343 in words is "one trillion, four hundred ninety-three billion, four hundred thirty million, five hundred ninety-four thousand, three hundred forty-three".
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