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149387352577 = 233963868043
BaseRepresentation
bin1000101100100000101…
…1100001101000000001
3112021121001122210121021
42023020023201220001
54421421130240302
6152343321225441
713535646355111
oct2131013415001
9467531583537
10149387352577
115839a2a2071
1224b51632281
1311119675ca8
147332275041
153d44e14437
hex22c82e1a01

149387352577 has 4 divisors (see below), whose sum is σ = 149451222960. Its totient is φ = 149323482196.

The previous prime is 149387352557. The next prime is 149387352589. The reversal of 149387352577 is 775253783941.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-149387352577 is a prime.

It is a super-2 number, since 2×1493873525772 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (149387352557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31931683 + ... + 31936360.

It is an arithmetic number, because the mean of its divisors is an integer number (37362805740).

Almost surely, 2149387352577 is an apocalyptic number.

It is an amenable number.

149387352577 is a deficient number, since it is larger than the sum of its proper divisors (63870383).

149387352577 is an equidigital number, since it uses as much as digits as its factorization.

149387352577 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63870382.

The product of its digits is 44452800, while the sum is 61.

The spelling of 149387352577 in words is "one hundred forty-nine billion, three hundred eighty-seven million, three hundred fifty-two thousand, five hundred seventy-seven".

Divisors: 1 2339 63868043 149387352577