Search a number
-
+
1494010740949 is a prime number
BaseRepresentation
bin10101101111011001111…
…110101100000011010101
312021211022011210020212021
4111233121332230003111
5143434213222202244
63102201123053141
7212636656523626
oct25573176540325
95254264706767
101494010740949
11526674129421
122016712111b1
13aab6663b73c
145244c055a4d
1528ce1684284
hex15bd9fac0d5

1494010740949 has 2 divisors, whose sum is σ = 1494010740950. Its totient is φ = 1494010740948.

The previous prime is 1494010740863. The next prime is 1494010740961. The reversal of 1494010740949 is 9490470104941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1494005067025 + 5673924 = 1222295^2 + 2382^2 .

It is a cyclic number.

It is not a de Polignac number, because 1494010740949 - 211 = 1494010738901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1494010740896 and 1494010740905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1494010740979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 747005370474 + 747005370475.

It is an arithmetic number, because the mean of its divisors is an integer number (747005370475).

Almost surely, 21494010740949 is an apocalyptic number.

It is an amenable number.

1494010740949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1494010740949 is an equidigital number, since it uses as much as digits as its factorization.

1494010740949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 52.

The spelling of 1494010740949 in words is "one trillion, four hundred ninety-four billion, ten million, seven hundred forty thousand, nine hundred forty-nine".