14940313433 has 4 divisors (see below), whose sum is σ = 14941325568. Its totient is φ = 14939301300.

The previous prime is 14940313417. The next prime is 14940313501. The reversal of 14940313433 is 33431304941.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14940313433 - 2⁴ = 14940313417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14940313393 and 14940313402.

It is not an unprimeable number, because it can be changed into a prime (14940313403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 483593 + ... + 513558.

It is an arithmetic number, because the mean of its divisors is an integer number (3735331392).

Almost surely, 2^14940313433 is an apocalyptic number.

It is an amenable number.

14940313433 is a deficient number, since it is larger than the sum of its proper divisors (1012135).

14940313433 is an equidigital number, since it uses as much as digits as its factorization.

14940313433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1012134.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 14940313433 in words is "fourteen billion, nine hundred forty million, three hundred thirteen thousand, four hundred thirty-three".