Base | Representation |
---|---|
bin | 1000101100101011111… |
… | …0111111111100100111 |
3 | 112021201100012002021211 |
4 | 2023022332333330213 |
5 | 4422020201304201 |
6 | 152352121452251 |
7 | 13540060306162 |
oct | 2131276777447 |
9 | 467640162254 |
10 | 149434400551 |
11 | 58413906997 |
12 | 24b65341087 |
13 | 11126339827 |
14 | 7338600ad9 |
15 | 3d49109651 |
hex | 22cafbff27 |
149434400551 has 2 divisors, whose sum is σ = 149434400552. Its totient is φ = 149434400550.
The previous prime is 149434400543. The next prime is 149434400627. The reversal of 149434400551 is 155004434941.
It is a weak prime.
It is an emirp because it is prime and its reverse (155004434941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 149434400551 - 23 = 149434400543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149434400051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74717200275 + 74717200276.
It is an arithmetic number, because the mean of its divisors is an integer number (74717200276).
Almost surely, 2149434400551 is an apocalyptic number.
149434400551 is a deficient number, since it is larger than the sum of its proper divisors (1).
149434400551 is an equidigital number, since it uses as much as digits as its factorization.
149434400551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 149434400551 in words is "one hundred forty-nine billion, four hundred thirty-four million, four hundred thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •