Base | Representation |
---|---|
bin | 10101101111101110010… |
… | …010000000100001011101 |
3 | 12021212011220200222102212 |
4 | 111233232102000201131 |
5 | 143440412421143403 |
6 | 3102255011330205 |
7 | 212651263615535 |
oct | 25575622004135 |
9 | 5255156628385 |
10 | 1494351349853 |
11 | 52682941998a |
12 | 2017472b0965 |
13 | aabbc08727b |
14 | 5248139a4c5 |
15 | 28d115154d8 |
hex | 15bee48085d |
1494351349853 has 2 divisors, whose sum is σ = 1494351349854. Its totient is φ = 1494351349852.
The previous prime is 1494351349849. The next prime is 1494351349867. The reversal of 1494351349853 is 3589431534941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 995918173849 + 498433176004 = 997957^2 + 705998^2 .
It is a cyclic number.
It is not a de Polignac number, because 1494351349853 - 22 = 1494351349849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1494351349792 and 1494351349801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1494351349453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 747175674926 + 747175674927.
It is an arithmetic number, because the mean of its divisors is an integer number (747175674927).
Almost surely, 21494351349853 is an apocalyptic number.
It is an amenable number.
1494351349853 is a deficient number, since it is larger than the sum of its proper divisors (1).
1494351349853 is an equidigital number, since it uses as much as digits as its factorization.
1494351349853 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27993600, while the sum is 59.
The spelling of 1494351349853 in words is "one trillion, four hundred ninety-four billion, three hundred fifty-one million, three hundred forty-nine thousand, eight hundred fifty-three".
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