Search a number
-
+
1494351349853 is a prime number
BaseRepresentation
bin10101101111101110010…
…010000000100001011101
312021212011220200222102212
4111233232102000201131
5143440412421143403
63102255011330205
7212651263615535
oct25575622004135
95255156628385
101494351349853
1152682941998a
122017472b0965
13aabbc08727b
145248139a4c5
1528d115154d8
hex15bee48085d

1494351349853 has 2 divisors, whose sum is σ = 1494351349854. Its totient is φ = 1494351349852.

The previous prime is 1494351349849. The next prime is 1494351349867. The reversal of 1494351349853 is 3589431534941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 995918173849 + 498433176004 = 997957^2 + 705998^2 .

It is a cyclic number.

It is not a de Polignac number, because 1494351349853 - 22 = 1494351349849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1494351349792 and 1494351349801.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1494351349453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 747175674926 + 747175674927.

It is an arithmetic number, because the mean of its divisors is an integer number (747175674927).

Almost surely, 21494351349853 is an apocalyptic number.

It is an amenable number.

1494351349853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1494351349853 is an equidigital number, since it uses as much as digits as its factorization.

1494351349853 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27993600, while the sum is 59.

The spelling of 1494351349853 in words is "one trillion, four hundred ninety-four billion, three hundred fifty-one million, three hundred forty-nine thousand, eight hundred fifty-three".