Base | Representation |
---|---|
bin | 1000101110000011001… |
… | …1001100010010111001 |
3 | 112022122211212222211210 |
4 | 2023200303030102321 |
5 | 4423242400413103 |
6 | 152452314313333 |
7 | 13552123266111 |
oct | 2134063142271 |
9 | 468584788753 |
10 | 149800404153 |
11 | 58591471904 |
12 | 25047a28849 |
13 | 111841070ca |
14 | 7371076041 |
15 | 3d6b304e03 |
hex | 22e0ccc4b9 |
149800404153 has 4 divisors (see below), whose sum is σ = 199733872208. Its totient is φ = 99866936100.
The previous prime is 149800404097. The next prime is 149800404157. The reversal of 149800404153 is 351404008941.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 149800404153 - 213 = 149800395961 is a prime.
It is a super-2 number, since 2×1498004041532 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (149800404157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24966734023 + ... + 24966734028.
It is an arithmetic number, because the mean of its divisors is an integer number (49933468052).
Almost surely, 2149800404153 is an apocalyptic number.
It is an amenable number.
149800404153 is a deficient number, since it is larger than the sum of its proper divisors (49933468055).
149800404153 is an equidigital number, since it uses as much as digits as its factorization.
149800404153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49933468054.
The product of its (nonzero) digits is 69120, while the sum is 39.
The spelling of 149800404153 in words is "one hundred forty-nine billion, eight hundred million, four hundred four thousand, one hundred fifty-three".
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