150000113 has 2 divisors, whose sum is σ = 150000114. Its totient is φ = 150000112.

The previous prime is 150000107. The next prime is 150000139. The reversal of 150000113 is 311000051.

150000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119617969 + 30382144 = 10937^2 + 5512^2 .

It is a cyclic number.

It is not a de Polignac number, because 150000113 - 2¹⁰ = 149999089 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 150000094 and 150000103.

It is not a weakly prime, because it can be changed into another prime (150000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75000056 + 75000057.

It is an arithmetic number, because the mean of its divisors is an integer number (75000057).

Almost surely, 2^150000113 is an apocalyptic number.

It is an amenable number.

150000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

150000113 is an equidigital number, since it uses as much as digits as its factorization.

150000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 150000113 is about 12247.4533271207. The cubic root of 150000113 is about 531.3294180140.

Adding to 150000113 its reverse (311000051), we get a palindrome (461000164).

The spelling of 150000113 in words is "one hundred fifty million, one hundred thirteen", and thus it is an aban number.