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150001117 = 721428731
BaseRepresentation
bin10001111000011…
…01010111011101
3101110020211211221
420330031113131
5301400013432
622515013341
73500663020
oct1074152735
9343224757
10150001117
1177743072
124229a251
13250cc576
1415cc91b7
15d27eb97
hex8f0d5dd

150001117 has 4 divisors (see below), whose sum is σ = 171429856. Its totient is φ = 128572380.

The previous prime is 150001109. The next prime is 150001151. The reversal of 150001117 is 711100051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150001117 - 23 = 150001109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 150001117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150001517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10714359 + ... + 10714372.

It is an arithmetic number, because the mean of its divisors is an integer number (42857464).

Almost surely, 2150001117 is an apocalyptic number.

It is an amenable number.

150001117 is a deficient number, since it is larger than the sum of its proper divisors (21428739).

150001117 is an equidigital number, since it uses as much as digits as its factorization.

150001117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21428738.

The product of its (nonzero) digits is 35, while the sum is 16.

The square root of 150001117 is about 12247.4943151650. The cubic root of 150001117 is about 531.3306034654.

Adding to 150001117 its reverse (711100051), we get a palindrome (861101168).

The spelling of 150001117 in words is "one hundred fifty million, one thousand, one hundred seventeen".

Divisors: 1 7 21428731 150001117