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15000241 = 71211271
BaseRepresentation
bin111001001110…
…001010110001
31001020002110111
4321032022301
512320001431
61253301321
7241333324
oct71161261
931202414
1015000241
1185159a3
125034841
1331527a9
141dc67bb
1514b47b1
hexe4e2b1

15000241 has 4 divisors (see below), whose sum is σ = 15211584. Its totient is φ = 14788900.

The previous prime is 15000233. The next prime is 15000257. The reversal of 15000241 is 14200051.

15000241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14200051 = 18117841.

It is a cyclic number.

It is not a de Polignac number, because 15000241 - 23 = 15000233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15000211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105565 + ... + 105706.

It is an arithmetic number, because the mean of its divisors is an integer number (3802896).

Almost surely, 215000241 is an apocalyptic number.

It is an amenable number.

15000241 is a deficient number, since it is larger than the sum of its proper divisors (211343).

15000241 is an equidigital number, since it uses as much as digits as its factorization.

15000241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211342.

The product of its (nonzero) digits is 40, while the sum is 13.

The square root of 15000241 is about 3873.0144590487. The cubic root of 15000241 is about 246.6225282196.

Adding to 15000241 its reverse (14200051), we get a palindrome (29200292).

The spelling of 15000241 in words is "fifteen million, two hundred forty-one", and thus it is an aban number.

Divisors: 1 71 211271 15000241