Base | Representation |
---|---|
bin | 10101110101000000111… |
… | …011110111000011110001 |
3 | 12022101211212202201211220 |
4 | 111311000323313003301 |
5 | 144034031423121040 |
6 | 3105034453255253 |
7 | 213242134203132 |
oct | 25650073670361 |
9 | 5271755681756 |
10 | 1500033020145 |
11 | 529184596970 |
12 | 202872034529 |
13 | ab5b620815a |
14 | 5285dbc3c89 |
15 | 2904521d2d0 |
hex | 15d40ef70f1 |
1500033020145 has 32 divisors (see below), whose sum is σ = 2618845793280. Its totient is φ = 727120309440.
The previous prime is 1500033020141. The next prime is 1500033020197. The reversal of 1500033020145 is 5410203300051.
It is not a de Polignac number, because 1500033020145 - 22 = 1500033020141 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1500033020141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 336555 + ... + 1764464.
It is an arithmetic number, because the mean of its divisors is an integer number (81838931040).
Almost surely, 21500033020145 is an apocalyptic number.
1500033020145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1500033020145 is a deficient number, since it is larger than the sum of its proper divisors (1118812773135).
1500033020145 is a wasteful number, since it uses less digits than its factorization.
1500033020145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2105365.
The product of its (nonzero) digits is 1800, while the sum is 24.
Adding to 1500033020145 its reverse (5410203300051), we get a palindrome (6910236320196).
The spelling of 1500033020145 in words is "one trillion, five hundred billion, thirty-three million, twenty thousand, one hundred forty-five".
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