150004344145 has 4 divisors (see below), whose sum is σ = 180005212980. Its totient is φ = 120003475312.

The previous prime is 150004344143. The next prime is 150004344169. The reversal of 150004344145 is 541443400051.

150004344145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 541443400051 = 71 ⋅7625963381.

It can be written as a sum of positive squares in 2 ways, for example, as 100329295504 + 49675048641 = 316748^2 + 222879^2 .

It is a cyclic number.

It is not a de Polignac number, because 150004344145 - 2¹ = 150004344143 is a prime.

It is not an unprimeable number, because it can be changed into a prime (150004344143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15000434410 + ... + 15000434419.

It is an arithmetic number, because the mean of its divisors is an integer number (45001303245).

Almost surely, 2^150004344145 is an apocalyptic number.

It is an amenable number.

150004344145 is a deficient number, since it is larger than the sum of its proper divisors (30000868835).

150004344145 is an equidigital number, since it uses as much as digits as its factorization.

150004344145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30000868834.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 150004344145 its reverse (541443400051), we get a palindrome (691447744196).

The spelling of 150004344145 in words is "one hundred fifty billion, four million, three hundred forty-four thousand, one hundred forty-five".