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150008030743 = 1491006765307
BaseRepresentation
bin1000101110110100101…
…1001110011000010111
3112100012022120111222111
42023231023032120113
54424204023440433
6152525052411451
713560224136334
oct2135513163027
9470168514874
10150008030743
115868869382a
12250a5476b87
13111b813188c
14739088198b
153d7e668dcd
hex22ed2ce617

150008030743 has 4 divisors (see below), whose sum is σ = 151014796200. Its totient is φ = 149001265288.

The previous prime is 150008030713. The next prime is 150008030749. The reversal of 150008030743 is 347030800051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150008030743 - 237 = 12569077271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150008030749) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503382505 + ... + 503382802.

It is an arithmetic number, because the mean of its divisors is an integer number (37753699050).

Almost surely, 2150008030743 is an apocalyptic number.

150008030743 is a deficient number, since it is larger than the sum of its proper divisors (1006765457).

150008030743 is a wasteful number, since it uses less digits than its factorization.

150008030743 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1006765456.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 150008030743 its reverse (347030800051), we get a palindrome (497038830794).

The spelling of 150008030743 in words is "one hundred fifty billion, eight million, thirty thousand, seven hundred forty-three".

Divisors: 1 149 1006765307 150008030743