1500113 has 2 divisors, whose sum is σ = 1500114. Its totient is φ = 1500112.

The previous prime is 1500101. The next prime is 1500127. The reversal of 1500113 is 3110051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1456849 + 43264 = 1207^2 + 208^2 .

It is a cyclic number.

It is not a de Polignac number, because 1500113 - 2⁸ = 1499857 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1500094 and 1500103.

It is not a weakly prime, because it can be changed into another prime (1500133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750056 + 750057.

It is an arithmetic number, because the mean of its divisors is an integer number (750057).

2^1500113 is an apocalyptic number.

It is an amenable number.

1500113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500113 is an equidigital number, since it uses as much as digits as its factorization.

1500113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 1500113 is about 1224.7910025796. The cubic root of 1500113 is about 114.4742986878.

Adding to 1500113 its reverse (3110051), we get a palindrome (4610164).

The spelling of 1500113 in words is "one million, five hundred thousand, one hundred thirteen".