15001240113 has 48 divisors (see below), whose sum is σ = 24346707840. Its totient is φ = 8850580992.

The previous prime is 15001240063. The next prime is 15001240129. The reversal of 15001240113 is 31104210051.

15001240113 is a `hidden beast` number, since 1 + 500 + 12 + 40 + 113 = 666.

It is not a de Polignac number, because 15001240113 - 2²² = 14997045809 is a prime.

It is not an unprimeable number, because it can be changed into a prime (15001240313) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 171495 + ... + 243747.

It is an arithmetic number, because the mean of its divisors is an integer number (507223080).

Almost surely, 2^15001240113 is an apocalyptic number.

It is an amenable number.

15001240113 is a deficient number, since it is larger than the sum of its proper divisors (9345467727).

15001240113 is a wasteful number, since it uses less digits than its factorization.

15001240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72358 (or 72355 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 15001240113 its reverse (31104210051), we get a palindrome (46105450164).

The spelling of 15001240113 in words is "fifteen billion, one million, two hundred forty thousand, one hundred thirteen".