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150015072841 is a prime number
BaseRepresentation
bin1000101110110110011…
…0000101101001001001
3112100012210211021220221
42023231212011221021
54424212324312331
6152525503350041
713560341036254
oct2135546055111
9470183737827
10150015072841
1158691663647
12250a78b2321
13111b9728cba
14739179609b
153d800aa711
hex22ed985a49

150015072841 has 2 divisors, whose sum is σ = 150015072842. Its totient is φ = 150015072840.

The previous prime is 150015072839. The next prime is 150015072847. The reversal of 150015072841 is 148270510051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143662982841 + 6352090000 = 379029^2 + 79700^2 .

It is a cyclic number.

It is not a de Polignac number, because 150015072841 - 21 = 150015072839 is a prime.

It is a super-2 number, since 2×1500150728412 (a number of 23 digits) contains 22 as substring.

Together with 150015072839, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 150015072797 and 150015072806.

It is not a weakly prime, because it can be changed into another prime (150015072847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75007536420 + 75007536421.

It is an arithmetic number, because the mean of its divisors is an integer number (75007536421).

Almost surely, 2150015072841 is an apocalyptic number.

It is an amenable number.

150015072841 is a deficient number, since it is larger than the sum of its proper divisors (1).

150015072841 is an equidigital number, since it uses as much as digits as its factorization.

150015072841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11200, while the sum is 34.

Adding to 150015072841 its reverse (148270510051), we get a palindrome (298285582892).

The spelling of 150015072841 in words is "one hundred fifty billion, fifteen million, seventy-two thousand, eight hundred forty-one".