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15002311425041 is a prime number
BaseRepresentation
bin1101101001001111111101…
…1100010111110000010001
31222010012120212200221022102
43122103333130113300101
53431244213211100131
651523544451250145
73105611156034113
oct332237734276021
958105525627272
1015002311425041
114864498765406
12182366b8a9955
1384a934064cc5
1439c1898793b3
151b03a05411cb
hexda4ff717c11

15002311425041 has 2 divisors, whose sum is σ = 15002311425042. Its totient is φ = 15002311425040.

The previous prime is 15002311425019. The next prime is 15002311425089. The reversal of 15002311425041 is 14052411320051.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10320021325441 + 4682290099600 = 3212479^2 + 2163860^2 .

It is a cyclic number.

It is not a de Polignac number, because 15002311425041 - 234 = 14985131555857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15002311424995 and 15002311425013.

It is not a weakly prime, because it can be changed into another prime (15002311425091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7501155712520 + 7501155712521.

It is an arithmetic number, because the mean of its divisors is an integer number (7501155712521).

Almost surely, 215002311425041 is an apocalyptic number.

It is an amenable number.

15002311425041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15002311425041 is an equidigital number, since it uses as much as digits as its factorization.

15002311425041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 15002311425041 its reverse (14052411320051), we get a palindrome (29054722745092).

The spelling of 15002311425041 in words is "fifteen trillion, two billion, three hundred eleven million, four hundred twenty-five thousand, forty-one".