Base | Representation |
---|---|
bin | 1101101001010000011010… |
… | …0000101100110100101001 |
3 | 1222010012220010211012011022 |
4 | 3122110012200230310221 |
5 | 3431244434040003200 |
6 | 51524004324542225 |
7 | 3105614125643000 |
oct | 332240640546451 |
9 | 58105803735138 |
10 | 15002430000425 |
11 | 486454969389a |
12 | 18236a3551975 |
13 | 84a9527b065a |
14 | 39c19b503c37 |
15 | 1b03aab64885 |
hex | da50682cd29 |
15002430000425 has 48 divisors (see below), whose sum is σ = 21743453270400. Its totient is φ = 10264155894720.
The previous prime is 15002430000407. The next prime is 15002430000431. The reversal of 15002430000425 is 52400003420051.
It is a happy number.
It is not a de Polignac number, because 15002430000425 - 232 = 14998135033129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15002430000394 and 15002430000403.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1824059 + ... + 5773391.
It is an arithmetic number, because the mean of its divisors is an integer number (452988609800).
Almost surely, 215002430000425 is an apocalyptic number.
It is an amenable number.
15002430000425 is a deficient number, since it is larger than the sum of its proper divisors (6741023269975).
15002430000425 is an equidigital number, since it uses as much as digits as its factorization.
15002430000425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3949807 (or 3949788 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 26.
Adding to 15002430000425 its reverse (52400003420051), we get a palindrome (67402433420476).
The spelling of 15002430000425 in words is "fifteen trillion, two billion, four hundred thirty million, four hundred twenty-five", and thus it is an aban number.
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