15003200113 has 4 divisors (see below), whose sum is σ = 16367127408. Its totient is φ = 13639272820.

The previous prime is 15003200099. The next prime is 15003200117. The reversal of 15003200113 is 31100230051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100230051 = 11 ⋅2827293641.

It is a cyclic number.

It is not a de Polignac number, because 15003200113 - 2²⁹ = 14466329201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15003200117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681963631 + ... + 681963652.

It is an arithmetic number, because the mean of its divisors is an integer number (4091781852).

Almost surely, 2^15003200113 is an apocalyptic number.

It is an amenable number.

15003200113 is a deficient number, since it is larger than the sum of its proper divisors (1363927295).

15003200113 is a wasteful number, since it uses less digits than its factorization.

15003200113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1363927294.

The product of its (nonzero) digits is 90, while the sum is 16.

Adding to 15003200113 its reverse (31100230051), we get a palindrome (46103430164).

The spelling of 15003200113 in words is "fifteen billion, three million, two hundred thousand, one hundred thirteen".