15004000117 has 2 divisors, whose sum is σ = 15004000118. Its totient is φ = 15004000116.

The previous prime is 15004000027. The next prime is 15004000139. The reversal of 15004000117 is 71100040051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8663700241 + 6340299876 = 93079^2 + 79626^2 .

It is a cyclic number.

It is not a de Polignac number, because 15004000117 - 2¹¹ = 15003998069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15004000094 and 15004000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15004003117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7502000058 + 7502000059.

It is an arithmetic number, because the mean of its divisors is an integer number (7502000059).

Almost surely, 2^15004000117 is an apocalyptic number.

It is an amenable number.

15004000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

15004000117 is an equidigital number, since it uses as much as digits as its factorization.

15004000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 140, while the sum is 19.

Adding to 15004000117 its reverse (71100040051), we get a palindrome (86104040168).

The spelling of 15004000117 in words is "fifteen billion, four million, one hundred seventeen", and thus it is an aban number.