15004013000 has 192 divisors, whose sum is σ = 37628744400. Its totient is φ = 5598412800.

The previous prime is 15004012999. The next prime is 15004013009. The reversal of 15004013000 is 31040051.

It can be written as a sum of positive squares in 24 ways, for example, as 6352408804 + 8651604196 = 79702^2 + 93014^2 .

It is a super-2 number, since 2×15004013000² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (15004013009) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 55776866 + ... + 55777134.

Almost surely, 2^15004013000 is an apocalyptic number.

15004013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 15004013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18814372200).

15004013000 is an abundant number, since it is smaller than the sum of its proper divisors (22624731400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

15004013000 is a wasteful number, since it uses less digits than its factorization.

15004013000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 517 (or 486 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 15004013000 its reverse (31040051), we get a palindrome (15035053051).

The spelling of 15004013000 in words is "fifteen billion, four million, thirteen thousand".