150041033514044 has 12 divisors (see below), whose sum is σ = 262590697446168. Its totient is φ = 75015119958000.

The previous prime is 150041033513989. The next prime is 150041033514131. The reversal of 150041033514044 is 440415330140051.

It is a super-3 number, since 3×150041033514044³ (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150041033513995 and 150041033514013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1349137202 + ... + 1349248409.

It is an arithmetic number, because the mean of its divisors is an integer number (21882558120514).

Almost surely, 2^{150041033514044} is an apocalyptic number.

It is an amenable number.

150041033514044 is a deficient number, since it is larger than the sum of its proper divisors (112549663932124).

150041033514044 is a wasteful number, since it uses less digits than its factorization.

150041033514044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2698399516 (or 2698399514 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 150041033514044 its reverse (440415330140051), we get a palindrome (590456363654095).

The spelling of 150041033514044 in words is "one hundred fifty trillion, forty-one billion, thirty-three million, five hundred fourteen thousand, forty-four".