150043326111047 has 4 divisors (see below), whose sum is σ = 150043401764256. Its totient is φ = 150043250457840.

The previous prime is 150043326111031. The next prime is 150043326111053. The reversal of 150043326111047 is 740111623340051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150043326111047 - 2⁴ = 150043326111031 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 150043326111047.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150043326111017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34769279 + ... + 38845712.

It is an arithmetic number, because the mean of its divisors is an integer number (37510850441064).

Almost surely, 2^{150043326111047} is an apocalyptic number.

150043326111047 is a deficient number, since it is larger than the sum of its proper divisors (75653209).

150043326111047 is an equidigital number, since it uses as much as digits as its factorization.

150043326111047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75653208.

The product of its (nonzero) digits is 60480, while the sum is 38.

Adding to 150043326111047 its reverse (740111623340051), we get a palindrome (890154949451098).

The spelling of 150043326111047 in words is "one hundred fifty trillion, forty-three billion, three hundred twenty-six million, one hundred eleven thousand, forty-seven".