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15005414381 is a prime number
BaseRepresentation
bin11011111100110010…
…00111001111101101
31102201202100000211012
431332121013033231
5221212341230011
610520550035005
71040563626536
oct157631071755
942652300735
1015005414381
11640018aa11
122aa9348a65
1315519c3629
14a24c3368d
155cc533a8b
hex37e6473ed

15005414381 has 2 divisors, whose sum is σ = 15005414382. Its totient is φ = 15005414380.

The previous prime is 15005414353. The next prime is 15005414393. The reversal of 15005414381 is 18341450051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8077515625 + 6927898756 = 89875^2 + 83234^2 .

It is an emirp because it is prime and its reverse (18341450051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15005414381 - 226 = 14938305517 is a prime.

It is a super-2 number, since 2×150054143812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15005414311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7502707190 + 7502707191.

It is an arithmetic number, because the mean of its divisors is an integer number (7502707191).

Almost surely, 215005414381 is an apocalyptic number.

It is an amenable number.

15005414381 is a deficient number, since it is larger than the sum of its proper divisors (1).

15005414381 is an equidigital number, since it uses as much as digits as its factorization.

15005414381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 32.

The spelling of 15005414381 in words is "fifteen billion, five million, four hundred fourteen thousand, three hundred eighty-one".