Base | Representation |
---|---|
bin | 1101101001100010100011… |
… | …1000000011010001001001 |
3 | 1222010200110122102201220121 |
4 | 3122120220320003101021 |
5 | 3431334423141424223 |
6 | 51530131550223241 |
7 | 3106145631063253 |
oct | 332305070032111 |
9 | 58120418381817 |
10 | 15007301514313 |
11 | 4866619513329 |
12 | 1824622ab4b21 |
13 | 84b24ab33854 |
14 | 39c5004bacd3 |
15 | 1b059368b15d |
hex | da628e03449 |
15007301514313 has 2 divisors, whose sum is σ = 15007301514314. Its totient is φ = 15007301514312.
The previous prime is 15007301514311. The next prime is 15007301514329. The reversal of 15007301514313 is 31341510370051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14919740561664 + 87560952649 = 3862608^2 + 295907^2 .
It is a cyclic number.
It is not a de Polignac number, because 15007301514313 - 21 = 15007301514311 is a prime.
Together with 15007301514311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (15007301514311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7503650757156 + 7503650757157.
It is an arithmetic number, because the mean of its divisors is an integer number (7503650757157).
Almost surely, 215007301514313 is an apocalyptic number.
It is an amenable number.
15007301514313 is a deficient number, since it is larger than the sum of its proper divisors (1).
15007301514313 is an equidigital number, since it uses as much as digits as its factorization.
15007301514313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 34.
Adding to 15007301514313 its reverse (31341510370051), we get a palindrome (46348811884364).
The spelling of 15007301514313 in words is "fifteen trillion, seven billion, three hundred one million, five hundred fourteen thousand, three hundred thirteen".
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