Base | Representation |
---|---|
bin | 11011111101010010… |
… | …01010010010010011 |
3 | 1102202001020202102001 |
4 | 31332221022102103 |
5 | 221214430334024 |
6 | 10521220134431 |
7 | 1040644450252 |
oct | 157651122223 |
9 | 42661222361 |
10 | 15009621139 |
11 | 64025a3577 |
12 | 2aaa837417 |
13 | 1552837336 |
14 | a2560a799 |
15 | 5ccab5244 |
hex | 37ea4a493 |
15009621139 has 2 divisors, whose sum is σ = 15009621140. Its totient is φ = 15009621138.
The previous prime is 15009621073. The next prime is 15009621149. The reversal of 15009621139 is 93112690051.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (93112690051) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15009621139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15009621098 and 15009621107.
It is not a weakly prime, because it can be changed into another prime (15009621149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7504810569 + 7504810570.
It is an arithmetic number, because the mean of its divisors is an integer number (7504810570).
Almost surely, 215009621139 is an apocalyptic number.
15009621139 is a deficient number, since it is larger than the sum of its proper divisors (1).
15009621139 is an equidigital number, since it uses as much as digits as its factorization.
15009621139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 15009621139 in words is "fifteen billion, nine million, six hundred twenty-one thousand, one hundred thirty-nine".
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