Base | Representation |
---|---|
bin | 1101101001101110001011… |
… | …0100111010110000111111 |
3 | 1222010222112001202222220112 |
4 | 3122123202310322300333 |
5 | 3431412320320131411 |
6 | 51531405313140235 |
7 | 3106316142330653 |
oct | 332334264726077 |
9 | 58128461688815 |
10 | 15010421255231 |
11 | 486797a528906 |
12 | 182515385a67b |
13 | 84b6272810ac |
14 | 39c718972a63 |
15 | 1b06c74d3b8b |
hex | da6e2d3ac3f |
15010421255231 has 24 divisors (see below), whose sum is σ = 16252101516000. Its totient is φ = 13845963966912.
The previous prime is 15010421255191. The next prime is 15010421255233. The reversal of 15010421255231 is 13255212401051.
It is a de Polignac number, because none of the positive numbers 2k-15010421255231 is a prime.
It is a super-2 number, since 2×150104212552312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15010421255233) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12127550 + ... + 13307828.
It is an arithmetic number, because the mean of its divisors is an integer number (677170896500).
Almost surely, 215010421255231 is an apocalyptic number.
15010421255231 is a deficient number, since it is larger than the sum of its proper divisors (1241680260769).
15010421255231 is a wasteful number, since it uses less digits than its factorization.
15010421255231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1181183 (or 1181160 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 15010421255231 its reverse (13255212401051), we get a palindrome (28265633656282).
The spelling of 15010421255231 in words is "fifteen trillion, ten billion, four hundred twenty-one million, two hundred fifty-five thousand, two hundred thirty-one".
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