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15014108117 = 69121728087
BaseRepresentation
bin11011111101110100…
…10001101111010101
31102202100200201101102
431332322101233111
5221222102424432
610521500235445
71041030545651
oct157672215725
942670621342
1015014108117
116405088718
122ab023bb85
131553748758
14a26057a61
155cd19e962
hex37ee91bd5

15014108117 has 4 divisors (see below), whose sum is σ = 15035836896. Its totient is φ = 14992379340.

The previous prime is 15014108101. The next prime is 15014108129. The reversal of 15014108117 is 71180141051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15014108117 - 24 = 15014108101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 15014108117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15014108147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10863353 + ... + 10864734.

It is an arithmetic number, because the mean of its divisors is an integer number (3758959224).

Almost surely, 215014108117 is an apocalyptic number.

It is an amenable number.

15014108117 is a deficient number, since it is larger than the sum of its proper divisors (21728779).

15014108117 is an equidigital number, since it uses as much as digits as its factorization.

15014108117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21728778.

The product of its (nonzero) digits is 1120, while the sum is 29.

Adding to 15014108117 its reverse (71180141051), we get a palindrome (86194249168).

The spelling of 15014108117 in words is "fifteen billion, fourteen million, one hundred eight thousand, one hundred seventeen".

Divisors: 1 691 21728087 15014108117