Base | Representation |
---|---|
bin | 100010001000111111001110… |
… | …100000011010111001011101 |
3 | 201200122022120010110010002002 |
4 | 202020333032200122321131 |
5 | 124140034202413244031 |
6 | 1251202304320412045 |
7 | 43425032235145244 |
oct | 4210771640327135 |
9 | 650568503403062 |
10 | 150151226306141 |
11 | 4392a8608a7365 |
12 | 14a10391a77025 |
13 | 65a227a1c03b8 |
14 | 29115029c795b |
15 | 1255ba09e3ccb |
hex | 888fce81ae5d |
150151226306141 has 2 divisors, whose sum is σ = 150151226306142. Its totient is φ = 150151226306140.
The previous prime is 150151226306041. The next prime is 150151226306171. The reversal of 150151226306141 is 141603622151051.
150151226306141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102399726525625 + 47751499780516 = 10119275^2 + 6910246^2 .
It is a cyclic number.
It is not a de Polignac number, because 150151226306141 - 218 = 150151226043997 is a prime.
It is a super-2 number, since 2×1501512263061412 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 150151226306095 and 150151226306104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150151226306171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75075613153070 + 75075613153071.
It is an arithmetic number, because the mean of its divisors is an integer number (75075613153071).
Almost surely, 2150151226306141 is an apocalyptic number.
It is an amenable number.
150151226306141 is a deficient number, since it is larger than the sum of its proper divisors (1).
150151226306141 is an equidigital number, since it uses as much as digits as its factorization.
150151226306141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 38.
Adding to 150151226306141 its reverse (141603622151051), we get a palindrome (291754848457192).
The spelling of 150151226306141 in words is "one hundred fifty trillion, one hundred fifty-one billion, two hundred twenty-six million, three hundred six thousand, one hundred forty-one".
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