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15020443121 is a prime number
BaseRepresentation
bin11011111110100100…
…11100010111110001
31102202210121120101012
431333102130113301
5221230213134441
610522244120305
71041135442235
oct157722342761
942683546335
1015020443121
116408715262
122ab2396095
131554b56088
14a26c265c5
155cda019eb
hex37f49c5f1

15020443121 has 2 divisors, whose sum is σ = 15020443122. Its totient is φ = 15020443120.

The previous prime is 15020443073. The next prime is 15020443157. The reversal of 15020443121 is 12134402051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12729480625 + 2290962496 = 112825^2 + 47864^2 .

It is an emirp because it is prime and its reverse (12134402051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15020443121 - 26 = 15020443057 is a prime.

It is a super-2 number, since 2×150204431212 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15020440121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7510221560 + 7510221561.

It is an arithmetic number, because the mean of its divisors is an integer number (7510221561).

Almost surely, 215020443121 is an apocalyptic number.

It is an amenable number.

15020443121 is a deficient number, since it is larger than the sum of its proper divisors (1).

15020443121 is an equidigital number, since it uses as much as digits as its factorization.

15020443121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 15020443121 its reverse (12134402051), we get a palindrome (27154845172).

The spelling of 15020443121 in words is "fifteen billion, twenty million, four hundred forty-three thousand, one hundred twenty-one".