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150225014512997 is a prime number
BaseRepresentation
bin100010001010000011111100…
…101000000101110101100101
3201200220101000112222101211022
4202022003330220011311211
5124142241312203403442
61251300230254020525
743433253621435614
oct4212037450056545
9650811015871738
10150225014512997
11439590863752a6
1214a227454a7745
1365a9209403368
142914d0278187b
151257a6d9913d2
hex88a0fca05d65

150225014512997 has 2 divisors, whose sum is σ = 150225014512998. Its totient is φ = 150225014512996.

The previous prime is 150225014512907. The next prime is 150225014513083. The reversal of 150225014512997 is 799215410522051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89990248169761 + 60234766343236 = 9486319^2 + 7761106^2 .

It is an emirp because it is prime and its reverse (799215410522051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150225014512997 - 210 = 150225014511973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150225014512907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75112507256498 + 75112507256499.

It is an arithmetic number, because the mean of its divisors is an integer number (75112507256499).

Almost surely, 2150225014512997 is an apocalyptic number.

It is an amenable number.

150225014512997 is a deficient number, since it is larger than the sum of its proper divisors (1).

150225014512997 is an equidigital number, since it uses as much as digits as its factorization.

150225014512997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268000, while the sum is 53.

The spelling of 150225014512997 in words is "one hundred fifty trillion, two hundred twenty-five billion, fourteen million, five hundred twelve thousand, nine hundred ninety-seven".